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    [討論]如何從zernike矩中提取出zernike系數(shù)啊 [復(fù)制鏈接]

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    離線jssylttc
     
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    只看樓主 倒序閱讀 樓主  發(fā)表于: 2012-04-23
    下面這個(gè)函數(shù)大家都不會(huì)陌生，計(jì)算zernike函數(shù)值的，并根據(jù)此可以還原出圖像來， ;v[F@O~*)  
    我輸入10階的n、m，r,theta為38025*1向量，最后得到的z是29525*10階的矩陣， kgEGL]G>  
    這個(gè)，跟我們用zygo干涉儀直接擬合出的36項(xiàng)zernike系數(shù)，有何關(guān)系呢？ s4@AK48  
    那些系數(shù)是通過對29525*10階的矩陣每列的值算出來的嘛？ VWI|`O.w  
    5dXC  
     "c\ZUx_i6  
    z%}^9  
     Ki,]*-XO  
    function z = zernfun(n,m,r,theta,nflag) j;=+5PY  
    %ZERNFUN Zernike functions of order N and frequency M on the unit circle. j\P47q'v#  
    %   Z = ZERNFUN(N,M,R,THETA) returns the Zernike functions of order N QNLkj`PL/  
    %   and angular frequency M, evaluated at positions (R,THETA) on the |4\.",Bg  
    %   unit circle.  N is a vector of positive integers (including 0), and 0mF3Vs`-Q  
    %   M is a vector with the same number of elements as N.  Each element j I_TN5  
    %   k of M must be a positive integer, with possible values M(k) = -N(k) 6w0/;8(_m  
    %   to +N(k) in steps of 2.  R is a vector of numbers between 0 and 1, |p4F^!9  
    %   and THETA is a vector of angles.  R and THETA must have the same ((SN We  
    %   length.  The output Z is a matrix with one column for every (N,M) isLIfE>  
    %   pair, and one row for every (R,THETA) pair. 1,p7Sl^h  
    % R